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36a^2+9=90
We move all terms to the left:
36a^2+9-(90)=0
We add all the numbers together, and all the variables
36a^2-81=0
a = 36; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·36·(-81)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-108}{2*36}=\frac{-108}{72} =-1+1/2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+108}{2*36}=\frac{108}{72} =1+1/2 $
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